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14 votes
What is the solution when the equation wx^2+w=0 is solved for x, where w is a positive integer?1.-12.03.64. ±i

User Pasi Jokinen
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1 Answer

16 votes
16 votes

Given equation is


wx^2+w=0

Here w is a positive integer.

Now, from the given equation


\begin{gathered} wx^2+w=0 \\ w(x^2+1)=0 \\ x^2+1=0\text{ \lbrack{}as w is a positive integer\rbrack} \\ x^2=-1 \\ x=\pm i\text{ i=}\sqrt[]{-1} \end{gathered}

Hence, the correct option is (4).

User Lorefnon
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