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1 vote
Which ordered pair makes both inequalities true?

y > –3x + 3

y > 2x – 2
a. (1,0)
b.(–1,1)
c.(2,2)
d.(0,3)

2 Answers

4 votes

Answer:

a. (1,0)

Explanation:

In order to calculate this, you just have ot insert the value of X into the inequality to evaluate it and see if it makes both correct, remember that the points are ordered as (x,y).

First enequality:


y=-3x+3\\y=-3(x)+3\\y=0

SO we know that the first one is true, the second one would be:


y=2x-2\\y=2(1)-2\\y=0\\

Now we know that both inequalities are true when evaluated for (1,0)

User Acemtp
by
8.3k points
3 votes
For a
0 > -3(1) + 3 i.e. 0 > 0 (not true)
For b
1 > -3(-1) + 3 i.e. 1 > 6 (not true)
For c
2 > -3(2) + 3 i.e. 2 > -3 (true)
2 > 2(2) - 2 i.e. 2 > 2 (not true)
For d
3 > -3(0) + 3 i.e. 3 > 3 (not true)

Therefore, none of the ordered pairs makes both inequalities correct.
User Danwood
by
7.3k points

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