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A solution has a pH of 2.5. What is its [OH-] ?

User TommyD
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pOH=14-pH=14-2.5=11.5 pH=-log[H+] 2.5=-log [H+] [H+]=10^-5/2 [OH-]=10^(14-5/2)=10^23/2
User Lapinkoira
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