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Solve the system of equations by the addition method 3x - 3y = 77x + 6y = 12

User Haya Raed
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We will solve the following system of equations by the addition method.


\mleft\{\begin{aligned}3x-3y=7 \\ 7x+6y=12\end{aligned}\mright.

For doing so, we multiply the first and the second equation by some numbers, with the intention of making the coefficients of the variable x opposites.

Having this in mind, we will multiply the first equation for -7, using the distributive property.


\begin{gathered} -7(3x-3y=7) \\ -21x+21y=-49 \end{gathered}

And the second equation by 3.


\begin{gathered} 3(7x+6y=12) \\ 21x+18y=36 \end{gathered}

And we obtain,


\mleft\{\begin{aligned}-21x+21y=-49 \\ 21x+18y=36\end{aligned}\mright.

The next step is to sum both equations:


\begin{gathered} -21x+21x+21y+18y=-49+36 \\ 0+21y+18y=-13 \\ 39y=-13 \\ y=-(13)/(39)=-(1)/(3) \end{gathered}

The last step is to replace the value on any of the two equations. We would do it on the first equation:


\begin{gathered} 3x-3(-(1)/(3))=7 \\ 3x+1=7 \\ 3x=7-1 \\ 3x=6 \\ x=(6)/(3)=2 \end{gathered}

This means that the solution is:


(x,y)=(2,-(1)/(3))

User Muhammad Ovi
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