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C 203 + 3C - 2Cr + 3CO If the experimental yield obtained was 18.45 g of Cr, but you should have produced 535 g of Cr, what is the percent yield?
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C 203 + 3C - 2Cr + 3CO

If the experimental yield obtained was 18.45 g of Cr, but you should have produced 535 g of Cr, what is the percent yield?

User Juanlumn
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Answer:

b I think

Step-by-step explanation:

my guyyyyanajja

User Marcanthony
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