159k views
1 vote
The length of a rectangular picture frame is 2 inches longer than twice the width. If the perimeter of the frame is 34 inches, find the dimensions of the frame.

User Pfranza
by
8.5k points

2 Answers

6 votes
Let,
the length of the rectangular picture frame be "x"
the width of the rectangular picture frame be "y"
Then, according to the question,
x = 2 + 2y ........................................................equation (1)

Perimeter = 34 inches

Now,
We have,
perimeter of the rectangular = 2 ( length + width)
34 = 2 ( x + y)
34 = 2 ( 2 + 2y + y)
34 = 2 (2 + 3y)
34 = 4 + 6y
34 - 4 = 6y
30 = 6y
30 / 6 = y
5 = y
Now,
taking equation (1)
x = 2 + 2y
substituting the value of "y" , we get,
x = 2 + 2(5)
x = 2 + 10
x = 12

So, the dimensions of the rectangular frame are 12 inches and 5 inches





User Peter Leimbigler
by
8.4k points
4 votes
The length, l, is 2 more than twice the width, w.
l= 2w+2 (2 more than twice w)
In a rectangle, we have two of the same lengths and two of the same widths.
2l+2w=34
Divide by 2 on each side.
l+w=17
We remember that l is 2w+2
Substituting that back in we get,
2w+2+w=17
3w+2=17
3w=15
w=5
We sub w back into l+w=17
l+5=17
l=12
The dimensions are 5 by 12 inches.
User Agamemnus
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories