Answer:
the vertex of the graph of the function g(x) = (x- 3)^2 + 9 is 3 units to the right and 9 units up of the vertex of the function f(x) = x^2.
Explanation:
the vertex of the graph of the function g(x) = (x- 3)^2 + 9 is 3 units to the right and 9 units up of the vertex of the function f(x) = x^2.