99.6k views
0 votes
100 POINTS!!! PLEASE HELP ME

100 POINTS!!! PLEASE HELP ME-example-1
100 POINTS!!! PLEASE HELP ME-example-1
100 POINTS!!! PLEASE HELP ME-example-2

2 Answers

8 votes

Answer:

angle WDB + angle WBX + angle BWK = 180 because it's a triangle

angle WDB + 66 + 22 (given) = 180 degrees

angle WDB = 180 - 66 - 22 = 92 degrees

Explanation:

User Bemmu
by
3.9k points
2 votes

Explanation:

For question 30, the first choice is not necessarily true. I attached a picture of what *could* be the parallelogram.

The first choice is true ONLY if the parallelogram is a square.

The second choice is not necessarily true either. It is true ONLY if the parallelogram is a rhombus (a square is also a rhombus, just for reference)

But opposite sides of a parallelogram are always equal

So the answer to question 30 are the first and second choices.

For question 31:

remember what I said about how opposite sides of a parallelogram are always equal? Well opposite angles are also always equal.

So angle BKX = angle BWX = angle XWB = 114 degrees

Angle BKW = angle XWK (using parallel lines) = angle XWB - angle BWK = 114 - 22 = 92 degrees

Angle WBX = angle BXK (using parallel lines too) = angle WXK - angle WXB.

Consecutive angles in a parallelogram add up to 180. So angle WXK + angle XWK = 180. angle WXK = 180 - angle XWK = 180 - 114 = 66 degrees.

angle WDB + angle WBX + angle BWK = 180 because it's a triangle

angle WDB + 66 (just figured it out) + 22 (given) = 180 degrees

angle WDB = 180 - 66 - 22 = 92 degrees

I hope I didn't do anything wrong lol

but I prolly did XD

User Jem
by
4.2k points