Question

If you have 9.4 x 10^24 molecules of gold how many grams of gold do you have?

Answer 1

3,075.61 grams

Explanations:

According to the Avogadro's constant;

`1\text{mole}=6.02*10^(23)molecules`

Convert the molecules of Gold to mole using the conversion factor:

`\begin{gathered} \text{moles of Au=}(9.4*10^(24))/(6.02*10^(23)) \\ \text{moles of Au=}1.56*10^(24-23) \\ \text{moles of Au=}1.56*10 \\ \text{moles of Au=}15.6\text{moles} \end{gathered}`

Determine the mass of Gold

`\begin{gathered} \text{Mass}=\text{mole}*\text{molar mass} \\ \text{Mass}=15.6\cancel{\text{moles}}*\frac{196.97g}{\cancel{\text{mol}}} \\ \text{Mass}=3,075.61\text{grams} \end{gathered}`

Hence the mass of Gold is 3,075.61 grams