The balanced equation that describes the reaction between potassium chromate and lead (II) chloride to produce potassium chloride and lead (II) chromate is expressed PbCl2 + K2CrO4 = 2KCl + PbCrO4. For every mole of K2Cr2O4, there is 1 mole of PbCrO4 produced. The number of moles of K2Cr2O4 is 0.1125 moles. The molar mass of PbCrO4 is 323.2 g/mol. THe mass of PbCrO4 then is 36.36 grams.