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A line passes through the origin and has a slope of –3. What is the equation of the line that is perpendicular to the first line and passes through the point (3, 4)?

1 Answer

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The given line has slope
m=-3. The slope of the line perpendicular to this line is
-(1)/(m) =(1)/(3).

Its equation is
y=(1)/(3) x+c. Since this line passes through,
(3,4),


4=(1)/(3) (3)+c\\ c=3

Thus the equation of the line in slope intercept form is
y=(1)/(3) x+3

User SeruK
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