Question

Calculate the [H3O+] and [OH-] for 0.0084 M H2SO4 Answer in units of M for both answers.

Answer 1

You can realize that sulfuric acid (H2SO4) is a strong acid because it can dissociate completely in an aqueous solution, so we can assume that the concentration [H3O+] is 0.0084 M.

We can find [OH-], using the following formula:

`\lbrack H_3O^+\rbrack\lbrack OH^-\rbrack=10^(-14).`

So, let's clear [OH-] and replace the data that we have:

`\begin{gathered} \lbrack OH^-\rbrack=(10^(-14))/(\lbrack H_3O^+\rbrack), \\ \lbrack OH^-\rbrack=(10^(-14))/(0.0084), \\ \lbrack OH^-\rbrack=1.190\cdot10^(-12)M\approx1.2\cdot10^(-12)M. \end{gathered}`

The answer is that we have 0.0084 M of [H3O+] and 1.2 x 10^(-12) M of [OH-].