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If I simplify (3b^3)^4 and in the end get 81b^12 how do I get there?
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Mar 7, 2015
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If I simplify (3b^3)^4 and in the end get 81b^12 how do I get there?
Mathematics
high-school
Halflings
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Halflings
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Everything inside of the parenthesis needs to be to the 4th root. So you can see it as:
3^4 * (b^3)^4
3^4 = 3*3*3*3 = 81
And using rules of exponents, you need to multiply those exponents.
b ^ (3*4) = b^12
Put them together... 81 b^12
Atfergs
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Mar 12, 2015
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