Question

Which best describes what happens when 50 mL of 0.0010M CaCl2 is added to 50 mL of 0.010M Na2SO4? (The Ksp of CaSO4 = 2.4 × 10–5.)

Answer 1

Answer:no precipitation occurs

Step-by-step explanation:

Answer 2

For [Ca +2 ]:
0.0010 mol/l · 0.05 l =
`5 * 10^(-5) mol`
For [ SO4 -2 ] :
0.01 mol/l · 0.05 l =
`5 * 10^(-4)`
Cumulative volume:
50 ml + 50 ml = 10 ml = 0.1 l
[Ca +2 ] =
`(5 * 10^(-5) )/(0.1) = 5 * 10^(-4)`
[SO4 - 2] =
`(5*10^(-4) )/(0.1)= 5* 10 ^(-3)`
Qc for CaSO4:
Qc =
`5 * 10 ^(-4) * 5 * 10^(-3) = 25 * 10 ^(-7)= 2.5 * 10 ^(-6)`
This is less than Ksp of CaSO4.
Answer: C ) No precipitation will occur.