Question

Hello, I need some assistance with this homework question please for precalculusHW Q41

Answer 1

`\begin{gathered} f(x)=4x^2-4 \\ For\text{ y-intercept} \\ x=0 \\ f(0)=4(0)^2-4 \\ f(0)=0-4 \\ f(0)=-4 \\ y-interpect\text{ \lparen0,}-4\text{\rparen} \\ For\text{ x-intercepts} \\ Factoring \\ \text{ }4x^2-4 \\ (2x+2)(2x-4) \\ (2x+2)(2x-4)=0 \\ For\text{ } \\ 2x+2=0 \\ 2x=-2 \\ x=-1 \\ (-1,0) \\ For\text{ } \\ 2x-2=0 \\ 2x=2 \\ x=1 \\ (1,0) \\ Hence \\ The\text{ x-intercepts are \lparen}-1,0\text{\rparen and \lparen1,0\rparen} \\ Therefore \\ The\text{ intercepts are \lparen0,-4\rparen, \lparen-1,0\rparen, \lparen1,0\rparen} \end{gathered}`