Question

which function in vertex form is equivalent to f(x) = x2 6x 3? f(x) = (x 3)2 3 f(x) = (x 3)2 − 6 f(x) = (x 6)2 3 f(x) = (x 6)2 − 6

Answer 1

B

Explanation:

Answer 2

Some operators are missed.

Any way I can guess that the function is x^2+6x+3

To find the vertex form of the equation you need to form a perfect square.

To do that add and subtract 9:

x^2 + 6x + 9 +3 - 9 = (x^2+6x+9) + (3-9) = (x+3)^2 -6

Answer: f(x) = (x+3)^2 - 6