31.4k views
2 votes
Find three consecutive odd intergers such that the sum of the largest and twice the smallest is 25

1 Answer

2 votes
Let the consecutive odd integers be:

x , x + 2, x + 4. Each integer increases by 2

Sum of largest and twice the smallest = 25

(x + 4) + 2*(x) = 25

x + 4 + 2x = 25

x + 2x = 25 - 4

3x = 21

x = 21/3

x = 7

Recall the consecutive odd integers are x, x + 2, x +4

7, 7 + 2 = 9, 9 + 2= 11

7, 9, 11.
User Nat Chouf
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories