Question

What is the value of x in the equation 1,331x3 − 216 = 0?

Answer 1

Value of
`x =(6)/(11)`

Step-by-step explanation:

Given the equation:
`1331x^3 -216 =0` .....[1]

Addition property of equality states that you add the number to both sides of an equation.

Add 216 to both sides of an equation [1]

`1331x^3 -216+216 =0+216`

Simplify

`1331x^3=216`

As,we know that
`11 * 11 * 11 =11^3 = 1331` and
`6 * 6 * 6 =6^3 = 216`

then the given equation becomes;
`11^3x^3=6^3`

or

`(11x)^3=6^3` ......[2]

Using
`a^3=b^3` then a=b.

[2] ⇒

11x =6

Divide both sides of an equation by 11, we get

`(11x)/(11) =(6)/(11)`

Simplify:

`x =(6)/(11)`

therefore, the value of x is,
`(6)/(11)`

Answer 2

In solving for the value of x in the equation 1331x^3 - 216 = 0, the steps are shown below:

1331x^3 - 216 = 0
(1331x^3 = 216) / 1331
x^3 = 216/1331
x = cube root (216/1331)
x = 6/11

Therefore, the value of x in the equation is 6/11.