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What is the absolute value of -4-√2i

User Rmbrad
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1 Answer

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For x +iy absolute value = √(x² + y²)

Absolute value of -4-√2i = -4-i√2, comparing x = -4, y= -√2

Absolute value = √( (-4)² + (-√2)²),

(-4)² = (-4)*(-4) = 16, (-√2)² = -√2 * -√2 = 2

=
√( (-4)² + (-√2)²)

= √(16 + 4) = √20

√20 = √(4*5) = √4 * √5 = 2√5

Absolute value = 2√5
User Vivekagr
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