219k views
5 votes
a country's population in 1993 was 94 million. in 1999 in was 99 million. estimate the population in 2005 using the exponential growth formula. round your answer to the nearest millionth. p=ae^kt

1 Answer

5 votes
Using the exponential growth formula P = Ae^kt, we can solve for the missing values.

Initially, let us solve for the growth factor k, using the values from 1993 and 1999.

In year 1999:
P = 99 million
A = 94 million
t = 1999 - 1993 = 6

Substituting the values into the equation:

99,000,000 = 94,000,000(e^k(6))
k = 8.6375x10^-3

Obtaining the population in 2005 using values from 1999:
P = ?
A = 99,000,000
k = 8.6375x10^-3
t = 2005 - 1999 = 6

Substituting the values into the equation:

P = 99,000,000(e^(8.6375x10^-3)(6))
P = 104,265,957.4

Approximating to the nearest million, the population in 2005 is 104 million.
User Barbra
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories