Question

Identify the 17th term of a geometric sequence where a1 = 16 and a5 = 150.06. Round the common ratio and 17th term to the nearest hundredth

Answer 1

arythmetic

an=a1+(n-1)d
an=nth term
a1=first term
n=which term
d=common differnece


a1=16
a5=150.06

a5=a1+(n-1)d=150.06
a5 means n=5
a1=16
150.06=16+(5-1)d
150.06=16+(4)d
minus 16 both sidesw
134.06=4d
divide both sides by 4
33.515=d

a17=a1+(17-1)d
a17=16+(16)(33.515)
a17=16+536.24
a17=552.24


the 17th term is 552.24