Question

A box contains 48 tickets for six door prizes. Six tickets are drawn, and not replaced, to declare the winners. If serge purchases 8 tickets, determine the probability that he wins

a) the first prize
b) the first and second prizes
c) all six prizes

Answer 1

the tickets aren't replaced, so multiply the probabilities, decreasing the denominator each time.

a) 1/48
b) (1/48)(1/47)
c) (1/48)(1/47)(1/46)(1/45)(1/44)(1/43)

Answer 2

a)
`P(1st\ prize)=(8)/(48)`
b)
`P(1st+2nd\ prizes)=(8C2)/(48C2)=.025`
c)
`P(all\ 6\ prizes)=(8C6)/(48C6)=0.000002`