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A 171 g sample of tetrafluoromethane (CF4) contains 90 g of carbon. What is the mass percent of fluorine in the compound?

the answer is 47.37%

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Mass of fluorine:171 g (compound ) - 90 ( carbon ) => 81 g of

fluorinepercent of fluorine in the compound:

( 81 g F ) / 171 ( compound ) x 100 %

= 0,4737 x 100 = 47,37%

hope this helps!
User MikeHunter
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To find the mass percent of fluorine in the compound, you must first determine the mass in g of fluorine in the compound. We do this by subtracting the mass of carbon from the total mass of the sample. From this we get 171 - 90 = 81g of fluorine in CF4 sample. Now to get the mass percent, we divide the fluorine mass by the sample mass to get the percent mass. 81/171 = .4737 which multiplied by 100 to get percentage give 47.37%.
User Mikel F
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