Question

A solution containing boric acid is mixed in a 1:25 ratio. If there are 900 mL of distilled water in the solution, how many mL of boric acid are there in the solution? Round your final answer to 1 decimal place if necessary.

Answer 1

In this problem, we can apply ratios to find the amount of boric acid in the solution.

We know that the ratio of boric acid to distilled water is 1:25. So, we can set up a proportion:

`\frac{\text{borc acid}}{\text{water}}=(1)/(25)`

Since we have a total of 900 mL of water, we can add the value of water and let x represent the boric acid:

`(x)/(900)=(1)/(25)`

Next, we can solve the proportion by cross multiplying:

`\begin{gathered} 25\cdot x=900\cdot1 \\ 25x=900 \end{gathered}`

Finally, we can divide by 25:

`\begin{gathered} (25x)/(25)=(900)/(25) \\ \\ x=36 \end{gathered}`

So, there are 36mL of boric acid.