Question

I wrote down the given for this geometric proof but I’m not sure where to go from here.

Answer 1

For this case we can do the following:

Statement Reason

AB = DC , AD= BC Given

AC = AC Common side

△ABC≅△ACD SSS criteria

∠DAC = ∠BCA By CPCT

CD∥AB Alternate angles are equal

∠DCA=∠CAB By CPCT

AD∥BC Alternate angles are equal

ABCD is parallelogram Opposite sides of quadrilateral are parallel.