Question

Write the equation of the line that is PARALLEL to the line y=-3x+12 and passes through the point (-1,6)

Answer 1

This problem can be solved using the point-slope formula:

`y-y_(1)=m(x-x_(1))`
Where m is the slope
x₁ is the x value provided and
y₁ is the y value provided.

Since this line is parallel, we know it will have the same slope as the original line, which is -3. The x₁ value is -1, and the y₁ value is 6. Plug these numbers into the equation and solve:


`y-y_(1)=m(x-x_(1))\\ y-6=-3(x+1)\\ y-6=-3x-3\\ \\y=-3x+3`