
moles of oxygen in reaction =
=
= 1.563 mol
Mole Ratio of oxygen to water in the reaction = 1 : 2
∴ for every mole of oxygen there is two moles of water
Thus moles of water in the reaction = (moles of oxygen) * 2
= 1.563 mol * 2
= 3.126 mol
Mass of water needed to produce amount of O = mol * molar mass
= (3.126 mol) * (18.01 g/mol)
= 56.299 g
≈ 56. 3 g