Question

Three multiplied by the sum of 4 and a number is the same as 18 more than the number. Find the number.. . If n is \"the number,\" which equation could be used to solve for the number?. . . 3n + 4 = n + 18. 4(3 + n) =n + 18. 3(4 + n) =n + 18. 3(4 + n) + 18 > n

Answer 1

Translate the statement to algebraic language: 1) Call x the unknown number 2) The sum of 4 and a number = 4 + x 3) Three multiplied by the sum of 4 and a number = 3(4 + x) 4) Is the same as 18 more than the number: 3( 4 + x) = 18 + x Solve the equation: 3*4 + 3x = 18 + x 3x - x = 18 - 12 2x = 6 x = 6/3 x = 2. The number is 2.

Answer 2

3(n+4)=n+18

The value of n is 3

Explanation:

Let n be the required number.

Sum of 4 and the number n is (n +4)

Three multiplied by the sum of 4 and the number= 3(n +4)

Now, 18 more than the number = (n + 18)

From, the given directions, we can write the equation

`3(n+4)=n+18`

Now, we solve this equation for n

Distribute 3 over the parenthesis

`3n+12=n+18`

Subtract n to both sides

`2n+12=18`

Subtract 12 to both sides

`2n=6`

Divide both sides by 2

`n=3`

Therefore, the required equation is

3(n+4)=n+18

The value of n is 3