37.9k views
1 vote
The position of a particle as it moves along the x axis is given for t>0 by x=(t^3 - 3t^2 +6t)m , where t in sec.Where id the particle wen it achieves its minimum speed (after t=0)?

1 Answer

6 votes
We are given with the equation of the distance of a particle expressed in x=(t^3 - 3t^2 -6t). To get the distance where minimum speed is achieved, we get the first derivative of the equation and equate to zero. hence, dx /dt = 3t^2 - 6t - 6 = 0. t is equal to 2.73 sec. The distance then after substituting to the original equation equal to 14.37 meters.
User Krishna Varma
by
8.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.