Question

The value of acceleration due to gravity (g) on a point. 10,000 kilometers above sea level is about. 1.49 meters/second2. How much will an object, which weighs. 98 newtons on the surface of Earth, weigh on this point? The value of acceleration due to gravity on Earth is 9.8 meters/second2.

Answer 1

14.90 Newtons

Step-by-step explanation:

As we know the formula for Force = m×g

where F is force applied on the mass by gravity, m is the mass and g = 9.8 m/sec² at the Earth.

Since F = 98 newton

g = 9.8
`\frac{\text{meter}}{\text{sec}^(2) }`

So by putting this value in the formula we can calculate the mass of the object

98 = 9.8×m

m =
`(98)/(9.8)=10` kg

Now we have to calculate the weight of the object at a point 10000 kilometers above the sea level where g becomes 1.49
`\frac{\text{meter}}{\text{sec}^(2) }`

By putting these values in the formula again

F = 10×1.49 = 14.90 Newton

Therefore, weight of the object will be = 14.90 newton.

Answer 2

We are given with 98 Newton weight of an object on the surface of the earth with an acceleration equal to 9.8 m/s2. This means the mass of the object is equal to 98/9.8 or 10 kg. Hence the weight of the object 10,000 kilometers above sea level where acceleration is 1.49 m/s2 is 14.9 Newtons.