132k views
1 vote
The molar mass of magnesium (Mg) is 24.30 g/mol. There are 6.02 x 10^23 atoms in 1 mol. How many atoms are present in 48.60 g of Mg?

2 Answers

2 votes

Answer:

In 48.6 grams of Mg there are 1.20 x 10²⁴

Step-by-step explanation:

A simple way to obtain the amount of atoms is by means of rules of three:

On one hand, you know the molar mass of Mg: 24.3 g / mol. This means that in one mole of Mg there are 24.3 grams. But you have 48.6 grams, so you must determine how many moles are that amount of mass. As mentioned earlier, you can calculate it using a rule of three: if there are 24.3 grams in a mole, how many moles are 48.6 grams?

moles of Mg=2 moles

On the other hand, you know that in one mole of Mg there are atoms. And you know that 48.6 grams are 2 moles. Then, you can reapply a simple rule of three: if in one mole there are atoms, how many atoms are in 2 moles?

number of atoms=1.20 x 10²⁴

Finally, you can say that in 48.6 grams of Mg, which are 2 moles, there are 1.20 x 10²⁴

User Xine
by
8.2k points
5 votes
Atoms of Mg = mol * L

mol of Mg =
(MASS)/(MOLAR MASS)

=
(48.60 g)/(24.30 g / mol)

= 2 mol

∴ atoms of Mg = 2 mol * ( 6.02 x 10²³)
= 1.204 x 10²⁴


User Alfredodeza
by
7.8k points