Question

help?!?!An observer (O) spots a plane flying at a 42° angle to his horizontal line of sight. If the plane is flying at an altitude of 15,000 ft., what is the distance (x) from the plane (P) to the observer (O)?

Answer 1

The distance from the plane to the observer is 13,506.06 ft. In the problem, the given values are 15,000 ft altitude of the plane and its opposite angle which is 42°.

x = 15,000 ft. * tan(42) = 13,506.06 ft