Question

Use a calculator to estimate the values of the following limits to two decimal places.. . lim . h → 0 (2.7h − 1/h) =. lim . h → 0 (2.8h − 1/h) =

Answer 1

The limits as h approaches 0 of the given expressions are both -Infinity.

Step-by-step explanation:

Given problem:

lim as h approaches 0 of (2.7h - 1/h)

Using a calculator, we can estimate the value of the limit to two decimal places.

For the expression (2.7h - 1/h), we substitute h = 0 into the expression to find the limit value.

Substituting h = 0 into the expression gives:

(2.7 * 0) - 1/0 = 0 - Infinity = -Infinity

Therefore, the limit as h approaches 0 of (2.7h - 1/h) is -Infinity.

Similarly, for the expression (2.8h - 1/h), substituting h = 0 gives:

(2.8 * 0) - 1/0 = 0 - Infinity = -Infinity

So, the limit as h approaches 0 of (2.8h - 1/h) is also -Infinity.

Answer 2

The correct answer to this question using the calculator is 'infinite.' These value are equal, they both lead to the same -infinity because 2.7h=2.8h=0.
You try to substitute with values or just directly get the answer by getting the slope.