Question

Which is the CORRECT answer choice?A.B,C OR D?This is a self-check activity

Answer 1

Given:

`3*2\begin{bmatrix}{-2} & {3} & {0} \\ {-4} & {2} & {6} \\ {6} & {-5} & {6}\end{bmatrix}`

Simplify,

`\begin{gathered} 3*2\begin{bmatrix}{-2} & {3} & {0} \\ {-4} & {2} & {6} \\ {6} & {-5} & {6}\end{bmatrix}=6\begin{bmatrix}{-2} & {3} & {0} \\ {-4} & {2} & {6} \\ {6} & {-5} & {6}\end{bmatrix} \\ =\begin{bmatrix}{-2\cdot6} & {3\cdot6} & {0\cdot6} \\ {-4\cdot6} & {2\cdot6} & {6\cdot6} \\ {6\cdot6} & {-5\cdot6} & {6\cdot6}\end{bmatrix}\ldots\text{ By applying scalar multiplication} \\ =\begin{bmatrix}{-12} & {18} & {0} \\ {-24} & {12} & {36} \\ {36} & {-30} & {36}\end{bmatrix} \end{gathered}`

Answer: option B)

`\begin{bmatrix}{-12} & {18} & {0} \\ {-24} & {12} & {36} \\ {36} & {-30} & {36}\end{bmatrix}`