Question

The distance between the points ( – 4, – 10) and (8,6).

Answer 1

PQ=√(x2-x1)²+(y2-y1)²

x1 = -4,x2 =8,y1= -10 ,y2=6

=√(8+4)²+(6+10)²

=√(12)²+(16)²

=√144+256

=√400

=20