Question

The school band wishes to raise a minimum of $800 by selling tickets to their holiday concert. They make $3 from each student ticket and $5 from each adult ticket. Let x represent the number of student tickets, and let y represent the number of adult tickets. Which linear inequality can be used to find the combinations of adult and student tickets that they can sell to meet their goal?

Answer 1

3x+5y>800 minimum is the least 

Answer 2

The linear inequality form is
`3x+5y>800`.

Explanation:

Given : The school band wishes to raise a minimum of $800 by selling tickets to their holiday concert. They make $3 from each student ticket and $5 from each adult ticket.

To find : Linear inequality can be used to find the combinations of adult and student tickets that they can sell to meet their goal?

Solution :

Let x represent the number of student tickets.

Let y represent the number of adult tickets.

Cost of ticket per student = $3

Cost of ticket of students = 3x

Cost of ticket per adult student = $5

Cost of ticket of adult students = 5x

The school band wishes to raise a minimum of $800 by selling tickets to their holiday concert.

i.e, minimum $800 is the least amount

The linear inequality form is
`3x+5y>800`.