Question

The slope-intercept form of the equation of a line that passes through point (–2, –13) is y = 5x – 3. What is the point-slope form of the equation for this line?

y – 13 = 5(x – 2)
y + 13 = 5(x + 2)
y – 2 = 5(x – 13)
y + 2 = 5(x + 13)

Answer 1

its b :)

Explanation:

i aint ever seen two pretty best friends

Answer 2

The point-slope form in general is
`y-y_1=m(x-x_1)`

With the coordinate (-2,-13) being
`(x_1,y_1)`, and the slope m, is 5, from y = 5x – 3,


`y-y_1=m(x-x_1)`

`y-(-13)=5(x-(-2))`

`y+13=5(x+2)`