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Use synthetic division to completely factor y=x^3-3x^2-10x+24 by x – 2.A. y = (x – 2)(x – 4)(x – 3)B. y = (x – 2)(x + 4)(x + 3)C. y = (x – 2)(x + 4)(x – 3)D. y = (x – 2)(x – 4)(x + 3)

Use synthetic division to completely factor y=x^3-3x^2-10x+24 by x – 2.A. y = (x – 2)(x-example-1
User BayerSe
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1 Answer

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18 votes

Answer:

D. y = (x – 2)(x – 4)(x + 3)

Explanation:

We want to completely factor the polynomial.

First, given the division of polynomials below:


(x^3-3x^2-10x+24)/(x-2)

To use synthetic division, set the denominator equal to 0 and solve for x:


x-2=0\implies x=2

Next, write the result(2) outside and the coefficients of the numerator inside as shown below:

Carry down the leading coefficient as shown below:

Multiply the carry down value(1) by the number outside (2) and write the number under the next column:

Repeat until it gets to the last column:

Therefore:


(x^(3)-3x^(2)-10x+24)/(x-2)=x^2-x-12

We factor the resulting quadratic expression:


\begin{gathered} x^2-x-12=x^2-4x+3x-12 \\ =x(x-4)+3(x-4) \\ =(x+3)(x-4) \end{gathered}

So, we have:


\begin{gathered} (x^(3)-3x^(2)-10x+24)/(x-2)=(x+3)(x-4) \\ \implies x^3-3x^2-10x+24=(x-2)\left(x-4\right)(x+3) \end{gathered}

Thus:


y=(x-2)\left(x-4\right)(x+3)

Option D is correct.

Use synthetic division to completely factor y=x^3-3x^2-10x+24 by x – 2.A. y = (x – 2)(x-example-1
Use synthetic division to completely factor y=x^3-3x^2-10x+24 by x – 2.A. y = (x – 2)(x-example-2
Use synthetic division to completely factor y=x^3-3x^2-10x+24 by x – 2.A. y = (x – 2)(x-example-3
Use synthetic division to completely factor y=x^3-3x^2-10x+24 by x – 2.A. y = (x – 2)(x-example-4
User Rama Priya
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2.7k points