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The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8
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The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line?

x – 4y = 8

x – 4y = 2

4x – y = 8

4x – y = 2

User Spinlock
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7.9k points

2 Answers

0 votes

Answer: A

Explanation:

Edgen 2023

User CodingBeginner
by
8.1k points
7 votes
Hello,

Answer A

The equation of the line passing through (-4,-3) and (12,1) is:

y+3=(x+4)*4/16
==>4y+12=x+4
==>x-4y=8


User Mihuilk
by
8.2k points
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