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The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8
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Sep 20, 2017
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The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line?
x – 4y = 8
x – 4y = 2
4x – y = 8
4x – y = 2
Mathematics
high-school
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Answer: A
Explanation:
Edgen 2023
CodingBeginner
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Sep 22, 2017
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CodingBeginner
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Hello,
Answer A
The equation of the line passing through (-4,-3) and (12,1) is:
y+3=(x+4)*4/16
==>4y+12=x+4
==>x-4y=8
Mihuilk
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Sep 25, 2017
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Mihuilk
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