We assume that the gas is an ideal gas so that we can use the ideal gas equation. It is expressed as PV=nRT. The calculations are as follows:
For the first conditions, we calculate the ratio of P and T which will be constant for the second condition.
P/T = nR / V = 1 mol (0.08206 atm L / mol K) / 24.5 L=0.0033 atm/K
We then solve for the amount of gas when the volume is equal to the volume of the tank.
n = (P/T)V / R = 0.0033 atm/K (170 L) / 0.08206 atm L/mol K
n = 6.94 mol
M = n x MM
M = 6.94 mol (32.0 g/mol)
M =222.04 g