Question

Divide m^2n^3/p^3 by mp/n^2

Answer 1

m^2n^3
----------
p^3 m^2n^3 n^2 mn^5
--------------- = -------------- * ---------- = -------------
mp p^3 mp p^4
-------
n^2

hope this will help you

Answer 2

Dividing
`(m^2n^3)/(p^3)` by
`(mp)/(n^2)` is
`mn^5p^(-4)`

Explanation:

Divide
`(m^2n^3)/(p^3)` by
`(mp)/(n^2)`

Solution :

We divide first expression by another,

`=((m^2n^3)/(p^3))/((mp)/(n^2))`

`=(m^2n^3)/(p^3)* (n^2)/(mp)`

`=(m^2n^5)/(mp^4)`

`=m^(2-1)n^5p^(-4)`

`=mn^5p^(-4)`

Therefore, Dividing
`(m^2n^3)/(p^3)` by
`(mp)/(n^2)` is
`mn^5p^(-4)`