Question

The intensity of a radio signal from the radio station varies inversely as the square of the distance from the station. suppose intensity is 8000 units at a distance of 2 miles. what will the intensity be at a distance of 11 miles? round your answer to the nearest unit.

Answer 1

Let I represent intensity and and d the distance;
I
`\alpha (1)/( d^(2) )`
When I=8000
8000=
`(k)/(4)`
k=32000
I=
`(32000)/(d)`
I=
`(32000)/(121)`
I=265 units