Question

Glucose is an important sugar in many biochemical reactions what is the molarity of a solution that contains 500 grams of glucose (molecular weight= 180.16 g/mol) in 7.02 liters of solution

a. .56M
b. .78 M
c. 3.85 M
b. 4.98 M

Answer 1

Number of moles :

500 / 180.16 => 2.775 moles

Volume = 0.72 L

M = n / V

M = 2.775 / 0.72

M = 3.85 M

hope this helps!

Answer 2

The correct answer is c.

Step-by-step explanation:

First, look for the same problem to verify that the correct volume is 0.702 L.

Now we must calculate the amount of glucose moles (n) in the 500g:

n =
`(500 g)/(180 (g)/(mol) )`

n = 2,7 mol

Molarity is given by moles of compound per liter. In this way, we calculate the molarity (M) as:

M =
`(2,7 mol)/(0,702 L)`

M =
`3,85(mol)/(L)`

Have a nice day!