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Find the derivative of: sqrt( 3x+sqrt( 3x+sqrt( 3x)))

User Squirkle
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1 Answer

4 votes
Hello,

y'=
( \sqrt{3x+ \sqrt{3x+ √(3x) } } )'


y'=\frac{(3+\frac{1}{2\sqrt{3x+√(3x)}})*(3+(3)/(2√(3x)))}{2( \sqrt{3x+ \sqrt{3x+ √(3x) } } )}

This make me think of a Ramanuyan 's formula of (x+1)


User FreeZey
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