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A circle is centered at the point (0, 0) and passes through the point (4, 5). The equation of this circle is?
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A circle is centered at the point (0, 0) and passes through the point (4, 5). The equation of this circle is?

User Zerk
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1 Answer

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If the point (4, 5) is on the curved part of the circle, then the
radius of the circle is the distance from its center to (4, 5).

The distance from (0, 0) to (4, 5) is

√(4²+5²) = √41 .

The equation of the circle is

x² + y² = 41 .
User Chrissukhram
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7.9k points
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