Question

The axis of symmetry for the graph of the function f(x) = 3x2 + bx + 4 is x = . What is the value of b?

Answer 1

b = ±i

Explanation:

Given the axis of symmetry of the equation f(x) = 3x²+bx+4 is x= b, to get the value of b we will substitute x = b into the equation and equate to zero as shown:

at f(b) = 0

f(b) = 3b² + b(b) + 4 = 0

3b²+b² + 4 = 0

4b² = -4

b² = -4/4

b² = -1

b = √-1

b = ±i

The value of b is a complex number ±i

Answer 2

The value of b is one. You just have to use the standard equation y = a + bx^2 + c. Get a, b, then c and from the given equation above you can derive a formula which is x is equal to the - b over 2 multiplied by a. if you get the value of x then substitute it to the equation and you will now get the value of b.