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The area of a playground is 234 yd2. The width of the playground is 5 yards longer than its length. Find the length and width of the playground. (1 point)

User Outluch
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1 Answer

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Let x be the length of the playground. With this representation, the width may be expressed as x + 5. The area of a rectangular figure is the product of its length and width.

A = L x W

A = (x)(x+5) = 234 yd²

Solving for the value of x in the equation gives an answer of x = 13 and x = -18. The second value of x is not applicable to the problem since a negative number cannot be a value for length. Below is the calculation of the dimensions.

Length = x = 13 yards
Width = x + 5 = 18 yards

Thus, the length and width of the playground are 13 and 18 yards, respectively.


User Ahala
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