Question

What are the zero(s) of the function f(x) = the quantity of 5 x squared minus 25 x, all over x?

A. x = 5
B.x = 0 and x = 5
C. x = 0
D.x = −5

Answer 1

0 =
`(5 x^(2)-25x )/(x)` , x ≠ 0 ( we can´t divide by zero)
5 x² - 25 x = 0
x ( 5 x - 25 ) = 0
5 x - 25 = 0
5 x = 25
x = 25 : 5 = 5
Answer: A) x = 5

Answer 2

Option A is correct that is x=5.

Explanation:

we have given a function
`f(x)=(5x^2-25x)/(x)`

Firstly, we will take the common factor out from numerator and denominator which is x and it will get cancel from the fraction we will get

`5x-25`

Now we will take again the common factor out which is 5 we will get

`5(x-5)`

Here, we will equate the expression to zero we will have

`5(x-5)=0`

We will get value of x

x=5

Therefore, option A is correct.