Question

Given that the molar mass of NaCl is 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of NaCl in 500. mL of solution?

Answer 1

Number of moles:

87.75 / 58.44 => 1.50 moles

Volume in liters:

500.0 / 1000 => 0.5 L

M = n / V

M = 1.50 / 0.5

M = 3.0 mol/L

hope this helps!

Answer 2

Answer: The molarity of the solution is 3 M.

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

`Molarity=(n* 1000)/(V_s)`

where,

n= moles of solute

`Moles=\frac{\text{Given mass}}{\text{Molar mass}}=(87.75g)/(58.44g/mol)=1.50mole`

`V_s` = volume of solution in ml = 500 ml

`Molarity=(1.50* 1000)/(500)=3M`

The molarity of a solution that contains 87.75 g of NaCl in 500 mL of solution is 3 M.