Question

Which monomial is a perfect cube? 16x627x832x1264x6

Answer 1

Starting from Monomial

`1. 16 x^6=2* 2* 2* 2* x^2* x^2* x^2`

in the factor of monomial , Number ,2 is more than 3 n, where, n=1,2,3,....., that is it is appearing four times. So, it is not a perfect cube.

`2.27 x^8=3* 3* 3* x^3* x^3* x^2`

The power of x should be multiple of 3.

Not a perfect cube.

`3. 32 x^(12)=2* 2* 2* 2* 2* x^4* x^4* x^4`

Number 2, should be equal to , 3 n, but here,it is equal to 5 times.So,

Not a perfect cube.

`4.64 x^6=4* 4* 4* x^2* x^2* x^2=(4)^3* (x^2)^3`

Perfect cube.

Option D

Answer 2

It is
`64 x^(6)` (D)
That is because:
`( 4 x^(2) ) ^(3) = 64 x^(6)`
Thank you.